Can't get #Param part of mysite/index.aspx#Param

All,

I thought I could use Request.Url to retrieve the "#Param" part of a url like "mysite/index.aspx#Param", but all I get is "mysite/index.aspx". I mean I was trying to get the whole thing and then parse the string to get it down to "Param".

Funny thing is what I'm getting is exactly the opposite of what I want. I want to get "Param" because there could be several on the page and I need to know which one, then process things.

Does anyone know how to do this? I've googled for a while and get nothing, and different version of the Request object get me the same result.

Thanks.

 

Something like mysite/index.aspx#Param is used to anchor to a section on your page.

For example : See : daspstaff00.web120.discountasp.net/default.aspx

I have the following on my page (at the bottom)
<div id='Param'>
Go here Section
</div>

The above url will just anchor to the section specified above.Therefore '#' cannot be used to pass parameters and hence 'Request.Url' will not include the # or anything after it.

Vikram

DiscountASP.NET
www.DiscountASP.NET

Post Edited (vvsharma) : 6/20/2007 2:08:55 AM GMT

 

yeah that's what I was using it for, to anchor to a certain point in the page. The problem is that point in the page is in an AJAX collapsible panel that defaults to collapsed, so I need to expand it if that anchor is in the url (or some other way to get it).

I can't use a link button and have to stick with an a href.

That's interesting about the url not returning it because I thought that,if it was in the address bar, it was part of the url.

If I use a query string I'll be able to tell which part of the page to go to but it won't actually go there unless I post back and redirect with the #param this time, which isn't good...unless having the page in an update panel reduces the page reloading. Hmmm...

Thanks for the reply.

 

I'm not sure what you mean. I want to get everything in the address bar, though specifically I want the part starting with the # sign. If I can get all of it I can at least parse the string but by default it is not retrieving the part I want.


Thanks.